electrical energy comes from protons

 

Proton and electron have the same electric charge but their masses are very different; being the mass of the proton more than 1000 times the mass of the electron.

All that exists is energy (e=mC^2) and this "is neither created nor destroyed" (this is always true).

So with the existing measurements I will do an experiment: disintegrate the mass of a proton to convert it into electricity and see its equivalence with the electron.

Because: can a proton generate by its mass more electrons with more charge than the proton itself? It does not make much sense...

Demonstration:

H (hydrogen) With an atomic mass of 1.00797 u (grams/mol or amu); periodic table.

The ratio of the mass of a proton to the mass of an electron is approximately 1836 to 1.

H+ (ion) mass 1.00794 (protium) is one proton.

Let's start:

We calculate the energy in the mass of a mole of protons with the formula e=mC^2.
1 mole of hydrogen(ion) 0.00100794 kg * 299792458^2 m/s = 90,589,129,485,599 joules.

"It is defined as the amount of charge carried in one second by an electric current of one ampere of intensity."

1 C = 1 A * s

1 C = 6,2401509 10^18 e- (number of electrons per coulomb)

W = V * A

1 J = 1 W/s (joules equals watts per second)

I will use 1 second.

90,589,129,485,599 W (equals to J) = 1 V * A

A = 90.589.129.485.599

calculate the number of electrons in those amperes (coulombs)

90,589,129,485,599 A × 6.241506 10^18 e- =

5,65412595219143072094×10^+32

"In the International System of Units the unit of electric charge is called the coulomb or coulomb (symbol C). It is defined as the amount of charge passing through the cross section of an electric conductor in one second, when the electric current is one ampere. Since the 26th General Conference on Weights and Measures in the International System of Units the elementary charge is defined as 1,602 176 634 × 10^-19 C, without uncertainty.2 Since the charge of the electron is of the same magnitude as that of the proton, but negative, it takes 6,241 509 074 460 763 × 10^18 electrons to assemble one coulomb of negative charge. "

We have here in this explanation that the charge of the electron is: 1,602 176 634 × 10^-19 C, without uncertainty.
and that " it takes 6,241 509 074 460 763 × 10^18 electrons to gather one coulomb of negative charge."

1 match the number of electrons in a coulomb (6.241 509 074 460 763 × 10^18) is the fundamental charge of an electron (1,602 176 634 × 10^-19 C "without uncertainty" )

then it is evident that:

5.6541252595219143072094 10^32 e- * 1.602 176 634 × 10^-19 C=.

90,589,084,862,941 A (amperes) or W (watts) or J (joules) for this case. Same number we started with.

this amount of electrons (produced by the mass of the proton) should be able to produce the same joules:

5,65412595219143072094 10^32 e-

we have the constant:

1 (J) Joules = 6.241506×10^18 (eV) Electron volts (matches electrons per coulomb).

1 eV = 1.6021774232023205232839638383821468729×10^-19 J (matches fundamental electron charge).

then:

 5,65412595219143072094×10^+32 × 1,6021774232052328396383821468729×10^-19 =

90,589,129,485,599 which were the joules produced by the disintegration of one mole of protons or hydrogen ions.
or hydrogen ions.

Then the energy was always of the proton.

How many protons are there in a mole of protons?

There should be exactly Avogadro's number.

"Avogadro's constant is the factor of proportionality between the number of particles or elementary entities and the amount of substance. Dividing the number of elementary entities, whatever they are, by Avogadro's constant gives the amount of substance."

(number atoms per mole of substance):

I.e. 6.02214 × 10^23 protons.

90,589,129,485,599 (were the J or A generated by 1 mole of hydrogen ions (protons)).

Each proton generated: 1.50426808×10^-10 J or A.

Why?

W=V × A where for V we took 1 volt.

If we take 1 eV or the charge of the electron

1 (J) Joules = 6.241506×10^18 (eV) Electron volts (matches electrons per coulomb)

Calculate voltage for energy generated by the mass of 1 proton (W=V×A)

1.50426808×10^-10 × W (J) × 6.241506E18×10^18 (eV)

940,394,092.77285 eV

A= 1.50426808×10^-10 W ÷ 940,394,092.77285 eV
= 1,59961456×10^-19 A

1W = 1V × 1A

1V = 1 ÷ 1,59961456×10^-19

6,25150599×10^+18

This would be the joules or watts produced by the energy contained in the mass of a proton.

Recall:

1 (J) Joules = 6.241506×10^18 (eV) Electron volts (coincides with electrons per coulomb).

1 eV = 1.602177423205232839638383821468729×10^-19 J (coincides with fundamental charge electron)

We have that the mass of the proton has generated:

6.25150599×10^+18 volts for 1 W (J) and 1A (matches electrons per coulomb).

1.59961456×10^-19 amperes watts joules for 1 V (coincides with fundamental charge electron)

The error is 0.1599613% and the relation between the energy generated by the mass of the proton and electron: 1/(e-)* with charges, both particles having opposite and equal charges.

*it is exactly e- and not 1/e- just an error I thought I corrected it

We have arrived at this value from the mass of the proton.

In quantum physics the electron is a fundamental particle while the proton is composed of 3 quarks...


Everything indicates that they are the same particle.

Currently, the explanation about electricity is maintained:

"Conduction electrons in a copper wire travel at about 10 ^ -9 c. That is about the walking speed for a human. Perhaps more like a 'snail's pace'. However, that is neither the speed of the signal nor the speed of the power in the wire. The signal speed, generally about the same as the energy speed, is much closer to the speed of light in a vacuum, c."

"The energy produced during the movement of the electrons through the wire is what generates the electricity but surprisingly the speed those electrons acquire in a copper wire like the ones that run through our house is less than 1 millimeter per second. To make a comparison, it is less than the speed at which a snail travels."

https://www.plcmadrid.es/a-que-velocidad-viaja-la-electricidad-por-el-cable/
It is known that electrical energy travels at the speed of light around power lines in the magnetic field that surrounds them, like a guided wave in the case of power lines.

Anyway, even a cable does not withstand that coming and going of electrons especially in high voltage ... (it is not like a tap).